Ca_{3}(PO_{4})_{2} + C

It is probably about a very long known method of obtaining phosphorus. But in the equation of reaction, there are coefficients 2 and 10 respectively.

That's what others have said. So the equation as written can signify simple mixing or using heat, is that correct?

I'm sorry, I'm ignorant, I don't know what you mean by "in the equation of reaction, there are coefficients 2 and 10 respectively."

I know there are various forms of phosphorus, some of which can spontaneously combust. Which is why I have been reluctant to add heat.

Anyway, I put the equation 'Ca

_{3}(PO

_{4})

_{2} + 10C" into the chemical reaction calculator at:

https://www.symbolab.com/solver/chemical-reaction-calculatorand the result was 24CaPO+10C

I don't understand that, you'd think some of the carbon would combine with the oxygen. As you might have guessed, I'm not a chemist.

At some point I'm going to try this, with a small amount, although I'm tempted to just get an allotrope of phosphorus and see if that will work just as well. I'll probably end up trying both.

Update: I probably put the equation in wrong, I didn't know how to input the sub's, for instance Ca sub 3. The calculator at

https://www.webqc.org/balance.php wouldn't even solve the equation.

Update 2: Maybe it's more right than wrong, I put in the suggested equation, Ca3(PO4)2+C into webqc.org/balance and got Ca3(PO4)2+C=CO+Ca3P2.

In addition, this is what it said under the equation line:

Balanced equation:

Ca3(PO4)2 + 8 C = 8 CO + Ca3P2

Reaction type: double replacement

So I think you must be correct, AWK, the point is to get phosphorus. How do I know how much heat to apply?