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Topic: OH- Concentration  (Read 1172 times)

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Offline Phoebe

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OH- Concentration
« on: August 28, 2019, 05:04:39 AM »
 Ok - I've another question I'm uncertain about.
 
This time I'm asked: If a highly concentrated ammonia solution is found to have a pH of 12.08. What is the hydroxide concentration [OH-(aq)] in mol L-1
(give answer to at least 3 sig figs)

So pH = 12.08, pOH is 14 - 12.08 pOH = 1.92,

Here's where I get confused:

I think to calculate the OH- I do [OH-] = 10-1.92

and get an answer of = 0.0120 mol L-1

But I'm not sure that's right, can anyone tell me if I've gone off track?

Offline AWK

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Re: OH- Concentration
« Reply #1 on: August 28, 2019, 07:45:33 AM »
OK
AWK

Offline Vidya

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Re: OH- Concentration
« Reply #2 on: September 01, 2019, 03:40:55 AM »
Ok - I've another question I'm uncertain about.
 
This time I'm asked: If a highly concentrated ammonia solution is found to have a pH of 12.08. What is the hydroxide concentration [OH-(aq)] in mol L-1
(give answer to at least 3 sig figs)

So pH = 12.08, pOH is 14 - 12.08 pOH = 1.92,

Here's where I get confused:

I think to calculate the OH- I do [OH-] = 10-1.92

and get an answer of = 0.0120 mol L-1

But I'm not sure that's right, can anyone tell me if I've gone off track?

Perfect and even sig -figs are also correct.

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