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Redox reaction issue with SO3 + H2O2 -> ? (in basic medium)

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murmelburmel:
(Basic medium!) My idea so far:

SO32- + H2O2  :rarrow: SO42- + H2O

Oxidation: SO32- + 2OH-  :rarrow: SO42- + H2O +2e-

Reduction: H2O2 :rarrow: H2O
...and here is the problem. I don't get the two sides balanced with OH- and H2O. Probably something really simple I'm missing but just can't figure it out.

Babcock_Hall:
You have not clearly stated what the question is and how much information you were given; therefore, it is difficult to tell what the question is vs. what is your work.  Your reduction half-cell does not show any electrons.

murmelburmel:
Sorry, I thought it was clear from the headline. The task is letting SO3 react with H2O2. We are not given a product. I thought SO4 and H2O would be the most likely so that's what I went with. I didn't add electrons because I learned to do those last. The problem is I don't get the atoms equal on both sides. Is H2O even right as the product of that reduction?

sjb:
Is SO3 sulfite (sulfate(IV) if you must) or sulfur trioxide? You use both which might be where the confusion is arising? As it is SO32- + H2O2  :rarrow: SO42- + H2O is balanced....

AWK:
https://www.wikiwand.com/en/Peroxymonosulfuric_acid

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