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Topic: How does the MoO4 serve as a catalyst in the iodine clock reaction  (Read 754 times)

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Offline ferretman25

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The iodine clock reaction involves 2 equations:

1. H2O2 (aq) + 2I-(aq)+ 2H+(aq) → 2H2O(l) + I2 (aq)
2. I2 (aq) + 2S2O32-(aq) → 2I-(aq) + S4O62-(aq)

Adding a solution of MoO4 catalyses the first reaction by providing an alternative pathway with a lower activation energy - 43 kJ/mol as compared to 52 kJ/mol in the uncatalysed reaction. What specifically is this 'alternative pathway' and in full detail, how does the MoO2 speed up the reaction rate of the first reaction?
« Last Edit: October 08, 2019, 03:47:31 PM by ferretman25 »

Offline AWK

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Re: How does the MoO4 serve as a catalyst in the iodine clock reaction
« Reply #1 on: October 11, 2019, 09:01:51 AM »
Some transition metals form many oxides with an interesting structure that are good catalysts for oxidation reactions, e.g. https://pubs.rsc.org/en/content/articlelanding/2011/dt/c0dt00706d/unauth#!divAbstract
AWK

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