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Topic: Expansion Coefficient  (Read 5164 times)

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JayShah

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Expansion Coefficient
« on: September 18, 2013, 09:58:50 PM »
The volume of a certain liquid varies with temperature as V=V{0.77 + 3.7 x 10^(-4)(T/K) + 1.52 x 10^(-6)(T/K)^2} where V is its volume at 298K. Calculate its expansion coefficient, alpha, at 310K.

How am I to go about doing this problem?
alpha is  = (1/V)(dv/dt)p

curiouscat

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Re: Expansion Coefficient
« Reply #1 on: September 19, 2013, 12:07:10 AM »
First, find that derivative.

JayShah

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Re: Expansion Coefficient
« Reply #2 on: September 19, 2013, 01:06:22 PM »
First, find that derivative.
Derivative of the equation given? Is the T a variable. After I take the derivative then what do I do? In respect to what variable do I take this derivative?

curiouscat

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Re: Expansion Coefficient
« Reply #3 on: September 19, 2013, 01:21:44 PM »
dV/dT

JayShah

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Re: Expansion Coefficient
« Reply #4 on: September 19, 2013, 11:24:54 PM »
Wow that was stupid easy. Thank you!

AWK

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Re: Expansion Coefficient
« Reply #5 on: November 07, 2019, 09:48:24 AM »
Wow that was stupid easy. Thank you!
If you write the formula correctly
AWK