**Reaction 1:**

I have this reaction:

https://imgur.com/MJBdOifFlowchart of experiment:

https://imgur.com/Yb6O7nzI know p-nitroaniline we use 10 mmol of it in the diazotization step and I know we use 10 mmol of the 2-napthol and since everything is 1:1 therefore I can multiply 10 mmol x product (para red which has 293.28 mw) to get a theoretical yield of 0.01 mols x 293.28 = 2.9328 theoretical yield of para red. Is the theoretical yield correct here? I did not consider the reagents Hcl and NaNO2, is that okay?

Now what we did here is that we split our product where half of it was coupled with 2-napthol and measured and weighted for a % yield and the other half was coupled with 2-napthol again but it was actually used for the dye process and not measured and weighted. Therefore, my final mass of the product was 0.634 g therefore 0.634/2.932 = 21.62% yield, is this % yield correct? Do I write down 21.62% and while it is very low, I can mention that half of it was used for the dye process. But even still if it wasn't cut in half it would be a final yield of 1.268 for a yield of 43.24 % which is still very low so what you guys think I should put down? I feel like since my final mass was 0.634 g therefore final yield was 21.62% regardless of what was split or not!

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**Reaction 2**:

**https://imgur.com/lB9yVCN**This time p-toluidine 10 mmol reacted with phenol 10 mmol to produce the azo dye product. The MW of final product is 212.245 mw therefore 0.01 mol x 212.245 g/mol = 2.122 theoretical yield, is this correct?

My final product was 1.2879 g which is divided by 2.122 g = 60.69% yield correct? Again it was split in 2 so my yield could have probably been higher. But your thoughts guys?