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Topic: Decomposition of KClO3  (Read 19246 times)

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Offline solomon_pup

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Decomposition of KClO3
« on: August 27, 2006, 12:38:50 PM »
Shalom!  I must say again this website is a very helpfull tool.  I need your help again!

There is a stoichiometry problem on my review

How many moles of KCL are formed by decomposing 0.50 moles of KClO3
Given:   2KClO3 ------>  2KCl  +  3O2
                                     <-------


a.  1.00    b.   0.25       c.   0.50       d.  0.75        e.  0.125

I keep getting .30

I am getting 245/.5  = 149/X  then getting .304

but the answer isnt there!  Perhaps I have my formula weights wrong?

I was sure I got this right:

What weight of O2 can be produced from 61.3 grams of KClO3?
Given :     2KClO3  ---------->   2KCl +  3O2

a... 8.10 g     b.  32.2  g      c.  27.9 g      d.  3.15 g     e.   24.0 g

I got E
« Last Edit: September 03, 2006, 05:01:32 PM by geodome »

Offline Will

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Re: Review of Chem 1 - 1 problem is catching me up!!
« Reply #1 on: August 27, 2006, 12:52:54 PM »
How many moles of KCL are formed by decomposing 0.50 moles of KClO3
Given:   2KClO3 ------>  2KCl  +  3O2

a.  1.00    b.   0.25       c.   0.50       d.  0.75        e.  0.125

0.50 moles of KClO3   --->   x moles of KCl
(Clue: 1:1 ratio)

I was sure I got this right:

What weight of O2 can be produced from 61.3 grams of KClO3?
Given : 2KClO3 ----------> 2KCl + 3O2

a... 8.10 g b. 32.2 g c. 27.9 g d. 3.15 g e. 24.0 g

I got E

Correct :)

Offline solomon_pup

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Re: Review of Chem 1 - 1 problem is catching me up!!
« Reply #2 on: August 27, 2006, 01:44:11 PM »
oh I suppose the correct answer on the first is just .50 because its the same coeffecient on KCl as on KClO3?

LOL it's only been a few months since Chem I I cant believe I'm allready this rusty!

Online Borek

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Re: Review of Chem 1 - 1 problem is catching me up!!
« Reply #3 on: August 27, 2006, 02:06:18 PM »
because its the same coeffecient on KCl as on KClO3?

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations

Read paragraph just below water synthesis equation.
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