[solomon_pup]

Shalom!  I must say again this website is a very helpfull tool.  I need your help again!

There is a stoichiometry problem on my review

How many moles of KCL are formed by decomposing 0.50 moles of KClO₃? 
Given:   2KClO₃ ------>  2KCl  +  3O₂
                                     <-------


a.  1.00    b.   0.25       c.   0.50       d.  0.75        e.  0.125

I keep getting .30

I am getting 245/.5  = 149/X  then getting .304

but the answer isnt there!  Perhaps I have my formula weights wrong?

I was sure I got this right:

What weight of O₂ can be produced from 61.3 grams of KClO₃?
Given :     2KClO₃  ---------->   2KCl +  3O₂

a... 8.10 g     b.  32.2  g      c.  27.9 g      d.  3.15 g     e.   24.0 g

I got E

[Will]

How many moles of KCL are formed by decomposing 0.50 moles of KClO₃? 
Given:   2KClO₃ ------>  2KCl  +  3O₂

a.  1.00    b.   0.25       c.   0.50       d.  0.75        e.  0.125

0.50 moles of KClO₃   --->   x moles of KCl
(Clue: 1:1 ratio)

I was sure I got this right:

What weight of O₂ can be produced from 61.3 grams of KClO₃?
Given : 2KClO₃ ----------> 2KCl + 3O₂

a... 8.10 g b. 32.2 g c. 27.9 g d. 3.15 g e. 24.0 g

I got E

Correct

[solomon_pup]

oh I suppose the correct answer on the first is just .50 because its the same coeffecient on KCl as on KClO₃?

LOL it's only been a few months since Chem I I cant believe I'm allready this rusty!

[Borek]

because its the same coeffecient on KCl as on KClO₃?

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations

Read paragraph just below water synthesis equation.