June 16, 2024, 01:05:03 AM
Forum Rules: Read This Before Posting


Topic: Hammett correlations involving heterocyclic aromatic rings  (Read 785 times)

0 Members and 1 Guest are viewing this topic.

Offline Babcock_Hall

  • Chemist
  • Sr. Member
  • *
  • Posts: 5636
  • Mole Snacks: +324/-24
Hammett correlations involving heterocyclic aromatic rings
« on: December 30, 2019, 10:24:58 AM »
I have been looking into Hammett correlations of both reactions between two small molecules and enzymes with electrophilic inactivators.  Some involve inactivators bearing aromatic rings.  The values for σmeta for the phenyl, 2-pyridyl, and 2-pyrimidinyl are 0.06, 0.33, and 0.23, respectively.  For additional comparison the values for 3-pyridyl and 4-pyridyl are 0.23 and 0.27, respectively.  These values are from a 1991 review article.

My question is why does 2-pyridyl have a more positive value of σmeta than does the 2-pyrimidinyl group?  Relative to the phenyl group, if one nitrogen is electron-withdrawing, it seems as if 2-nitrogens should be more electron-withdrawing.

Offline pgk

  • Chemist
  • Full Member
  • *
  • Posts: 892
  • Mole Snacks: +97/-24
Re: Hammett correlations involving heterocyclic aromatic rings
« Reply #1 on: December 31, 2019, 10:17:42 AM »
The electron-withdrawing effects of 1- and 3- nitrogen atoms of are competitive, as concluded by drawing the free electron pairs and arrows accompanied, conjugation forms of pyrimidine.

Sponsored Links