[yodalr]

We needed to balance this equation so that there would be no ions in the end result (By adding SO4**2- for example). But I couldn't figure out how to solve it as I ended up with different charges on either sides. How should I continue this?
https://i.imgur.com/bT3jeHF.png

My initial idea was to add five SO**2- To both sides, but that would still leave me with 10 H+ cations on the left side.

NB! Our teacher makes mistakes quite often in the given assignments, and I'm never sure if I'm in the wrong or he is.

[chenbeier]

The Redox reaction is not balanced. If you reduce nitric acid OH- make no sense, because acidic condition.

1. Built redox pair, which one in this case
2. Reduction by using H+ on educt side and water on product side
3. Balance the charge with electrons
4. Do the same for oxidation, here only change metal to ion
5. Combine the two equations by multiplication and balancing after addition

Try this first