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Dilute 20% solution to create 3 litres of 1% solution

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**saparama**:

The problem is: We have a 20% solution of NaCl and we want to create 3 litres of 1% NaCl solution. Question is how many litres of 20% solution and how many litres of water should we use to create such thing.

It was on my exam and I tried to use c1.V1 = c2.V2 From equation m1.w1 = m2.w2 i found out that m1 = 0,05.m2 but that is all I got. Can someone please help me? How should I continue? Does this problem have a solution?

**chenbeier**:

Use cross rule

20. 1 weight part

1

0. 19 weight part

______________

20 weight part = 3 kg

You need the specific gravity to convert to volume.

If you calculate in mass 3 kg 1% solution = 20 weight parts

You need 150 g 20% solution ( 1 weight part) and 2,85 kg (19 weight part) of water.

**saparama**:

--- Quote from: chenbeier on January 16, 2020, 04:10:27 PM ---Use cross rule

20. 1 weight part

1

0. 19 weight part

______________

20 weight part = 3 kg

You need the specific gravity to convert to volume.

If you calculate in mass 3 kg 1% solution = 20 weight parts

You need 150 g 20% solution ( 1 weight part) and 2,85 kg (19 weight part) of water.

--- End quote ---

Thank you very much for you answer but I have a question. They wanted the answer in volumes. Can I use 0,150 litres and 2,85 litres?

**Borek**:

These will be only approximate, density of the 20% NaCl solution is around 1.15 g/mL, so 150 g is quite far from being 150 mL,

If you were not given densities 150 mL is your best bet though.

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