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Topic: Identity of unknown gas.  (Read 1801 times)

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Offline humanjoj27

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Identity of unknown gas.
« on: January 18, 2020, 04:04:34 AM »
Hello everyone,,
my teacher just got a question in the world wide web and changed it from 0.355 to 0.255

An unknown gas composed of homonuclear diatomic molecules effuses at a rate that in only 0.255 times that of O2 at the same temperature. what is the identity of unknown gas.

rx/rO2 = sqr mO2/M
rx = 0.255 x rO2

rx/rO2 = 0.255 = sqr 32.0g/mol / mx

solving for uknown molar mass
Mx :
32.0g/mol / mx = (0.255)^2 = 0.065025

Mx = 32.0g/mol / 0.065025 = 492.11 g / mol which is ? gas and cant find it on internet.

Offline AWK

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Re: Identity of unknown gas.
« Reply #1 on: January 18, 2020, 06:07:47 AM »
Use correctly Graham's Law

https://wiki2.org/en/Graham%27s_law
AWK

Offline MNIO

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Re: Identity of unknown gas.
« Reply #2 on: January 18, 2020, 05:46:40 PM »
via Graham's law
  (rate1 / rate2) = √(mw2 / mw1)

doing a bit of algebra
  (rate1 / rate2)2 = mw2 / mw1
  mw2 = mw1 * (rate1 / rate2)2

the original 0.355 gives
  mw2 = 32.00g/mole * (rate1 / 0.355*rate1)2 = 254 g/mol

your new # yields
  mw2 = 32.00g/mole * (rate1 / 0.255*rate1)2 = 492 g/mol

*********
if you're instructor simply pinched a problem off the internet and changed 0.355 to 0.255, then there is no reason to assume you'll be able to find a real gas with that molar mass.

Offline AWK

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Re: Identity of unknown gas.
« Reply #3 on: January 19, 2020, 02:13:50 AM »
Even the textbook idea with a 0.355 ratio is suspicious. Iodine boils at a temperature above 180°C.
But the inverse of 1/0.255 gives MW close to the molecular weight of hydrogen. Probably your teacher was thinking about it.
AWK

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