Previously, I dissolved CaCO3 into solution using CO2 then used electrochemistry to raise the pH and precipitate CaCO3 on the surface of my electrode (see reaction scheme in LHS of table below).
I now want to do the same for BaSO4. Sulphur dioxide has similar speciation characteristics to CO2, so I thought it might be possible...
But I am confused what the reactions would be, the sulphur dioxide would be left bubbling into the solution overnight, so I'm predicting a pH of around 2 to 4. If I assume that the liquid becomes ##SO_{(2)(aq)}## I end up with ##BaSO_{3}## not ##BaSO_{4}##...
If I assume ##HSO_{3}^{-}##, or ##HS_{2}O_{5}^{-}##, or ##S_{2}O_{5}^{2-}## I get something else. In fact the reaction between sulphur dioxide and water is written as ##H_{2}SO_{3}##.
Am I comparing apples and oranges? Getting a little lost here. Can I use sulphur dioxide as I did the carbon dioxide?
Thanks for any help.