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Calculating number of grams of solute from molal concentration

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DilutedBrain:
The Problem:Calculate the number of grams of solute necessary to prepare 700 grams of 0.6m H2SO4 solution.

The attempt: I tried to find the answer using the formula:

grams solute = molality * Molecular weight of H2SO4*L solvent

...until I realized there is no solvent in the problem. I tried to find the kilograms of solvent but there's no way I can find it without grams of solute or the weight percent. What formula should I use? Should I convert the molal concentration into molar concentration then find the grams of solute from there?

AWK:
Calculate the mass of sulfuric acid needed to make 0.6m from 1kg of water, calculate the mass of this solution, calculate the scaling factor to 700g and apply it to the previously calculated mass of sulfuric acid.
Show your result.

DilutedBrain:
So... this is what I did

1. Calculate the mass of Sulfuric acid...

mass H2SO4 = O.6m * 98 g/mol (MW of H2SO4) * 1000 grams of water

I got 58,800 g H2SO4

2. Calculate the mass of this solution

I assumed the H2SO4 solution so I based the answer to the given of 700g H2SO4 solution. I don't get this one so I assumed this completely.

3. What I did for the scaling factor is this

58,800 grams/700 grams = 84 grams

...did I got this one right? or I failed?  ???

AWK:
The scaling (down) factor is 700/1058.8

DilutedBrain:
Ohh... May I ask where the 1058.8 came from?

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