Thank you, sir.

So, I thought about a possible way how to calculate it... Here it is.

a) Burning 1 kg of H2.

2 H2 (g) + O2 (g) => 2 H2O (g)

Mr = 2

Q1 = 2 . - 241,8 = - 483,6 kJ.mol-1

n = m/M = 1000 g / 2 g.mol-1 = 500 mol

E = 500 . - 483,6 = - 241 800 kJ = - 241,8 MJ

b) Burning 1 kg of syntin.

C10H16 + 14 O2 => 10 CO2 + 8 H2O

Mr = 136,238

Q2 = (10 . – 393,5) + (8 . - 241,8) = - 5889,4 kJ.mol-1

n = m/M = 1000/136,238 = 7,34 mol

E = 7,34 . - 5889,4 = - 43228,196 kJ = - 43,228196 MJ.

Is that right?

I presume not, but otherwise I cannot come to any other solution. Thanks.