December 03, 2020, 08:13:17 PM
Forum Rules: Read This Before Posting

### Topic: relaxation time  (Read 460 times)

0 Members and 1 Guest are viewing this topic.

#### Lisa_JO

• New Member
• Posts: 4
• Mole Snacks: +0/-0
##### relaxation time
« on: February 19, 2020, 10:07:15 PM »
The reversible reaction, A(aq) + H2O(l)---> P(aq)
is first-order in A(aq) and P(aq), and pseudo-zero order in H2O(l). What must be
the most appropriate expression for the relaxation time, τ, when the reaction
returns to its equilibrium after a sudden increase in temperature?

the key answer is: relation time=1/kf+kr but my question is why not 1/kf( [A]+kr [p] since only water will be eliminated?

#### mjc123

• Chemist
• Sr. Member
• Posts: 1804
• Mole Snacks: +254/-12
##### Re: relaxation time
« Reply #1 on: February 20, 2020, 08:40:27 AM »
For a start, you can see your proposed answer is wrong, because for a first order reaction the rate constant has the dimensions 1/time.
For a more thorough answer, let the equilibrium be displaced slightly so that the concentrations are [A]e + δ and [P]e - δ. Set up a differential equation for the rate of change of δ and solve it.

#### Lisa_JO

• New Member
• Posts: 4
• Mole Snacks: +0/-0
##### Re: relaxation time
« Reply #2 on: February 20, 2020, 09:21:46 AM »

Thank you for the explanation, but I still don't get it when I followed these steps I didn't get the key answer "1/Kr+Kf "because the reactant didn't got cancel out with the product that's what am confused about

#### mjc123

• Chemist
• Sr. Member
• Posts: 1804
• Mole Snacks: +254/-12
##### Re: relaxation time
« Reply #3 on: February 20, 2020, 12:18:16 PM »