So, when EtOH and Water are distilled, they reach the 78.17C minimum-boiling azeotrope, at which point the compositions of the vapor and liquid are the same. That would mean that the liquid distilland will be 4% water and 96% EtOH by mass.
However, in looking through my old P-Chem notes, I found that the professor noted that the distilland will be composed of pure water. From what I understand, the distilland is supposed to be the sample that is left in the distillation flask, and the distillate is in the receiving flask. I would assume that both flasks contain the same mixtures. Is it possible for the distilland to be pure water?
Also, from a 50% EtOH/50% water mixture, is it possible to go towards making a pure water distillate by heating the vapor to, say, 100C, and then collecting the vapor and condensing it?