April 23, 2024, 02:36:48 AM
Forum Rules: Read This Before Posting


Topic: Combustion Thermochemistry  (Read 904 times)

0 Members and 1 Guest are viewing this topic.

Offline Algebrasucksbutilikeit

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Combustion Thermochemistry
« on: April 03, 2020, 08:45:39 PM »
I'm currently working on a Thermochemistry problem and i have no idea how to do this. I just learned it today :/

Using the information in the table to the right, calculate the enthalpy of combustion of each of the following substances:
Acetylene:    kJ/mol
Ethanol:      kJ/mol

Compound:           Enthalpy of formation:
methane(CH4)             -74.8
acetylene(C2H2)           226.77
ethanol(C2H6O)            -235.1
Carbon Dioxide(CO2)     -393.5
Water(H2o)                   -241.82

Please help me. I don't just want the answers, i want the work to go with it...any help given is much appreciated! Thank you :)

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7979
  • Mole Snacks: +555/-93
  • Gender: Male
AWK

Offline Enthalpy

  • Chemist
  • Sr. Member
  • *
  • Posts: 4041
  • Mole Snacks: +304/-59
Re: Combustion Thermochemistry
« Reply #2 on: April 06, 2020, 06:08:53 AM »
If you learned it today, it must be in the lesson I guess.

Write a balanced chemical reaction, count the heats of formation of the reactants and products, deduce the heat of reaction.

Apparently, you can suppose that the combustion produces CO2.

The heat of formation for water is indicated for vapour. Your computation will hence result in the "lower heating power".

Heats of formation given to 0.01kJ/mol are grotesque. I'd be very happy if they were known to 1kJ/mol.

Sponsored Links