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Topic: Aq. Cu(II) with Sugar  (Read 9569 times)

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Offline peacefulltortoise

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Aq. Cu(II) with Sugar
« on: September 08, 2006, 11:28:36 AM »
I have 2 related problems:
1, Why only polyol with at least 2 OH's Carbons beside each other could make deep blue solution with Cu(OH)2? At first I thought it was because of the 5 atoms ring that is stable, but then someone said the complex must be more stable with 6 atoms ring as the 2 OH's are separated by another Carbon. Do you have any idea?
2, Sucrose haven't got any couple of OH groups which are cis, how could sucrose make deep blue solution with Cu(OH)2?

Offline peacefulltortoise

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Re: Evolution of Krebs Cycle- why 6C?
« Reply #1 on: September 11, 2006, 07:37:47 AM »
Hey guys, please tell me what you think about my questions.

Offline Albert

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Re: Aq. Cu(II) with Sugar
« Reply #2 on: September 12, 2006, 04:17:57 AM »
2, Sucrose haven't got any couple of OH groups which are cis, how could sucrose make deep blue solution with Cu(OH)2?

Sucrose is the most frequent example of NON-reducing sugar. However, you shouldn't be surprised: copper hydroxide is actually blue. You should be shocked if you see a reddish precipitate.

By the way, why is this post here? It must be in the biochemistry forum.

Offline peacefulltortoise

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Re: Aq. Cu(II) with Sugar
« Reply #3 on: September 12, 2006, 06:33:00 AM »
I don't understand. So what we have known is not true, isn't it? Could you please explain me more? By the way, I did not mean about reductibility of sugar, I meant the property of polyol compoud. Thank you for your answer.

Offline AWK

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Re: Aq. Cu(II) with Sugar
« Reply #4 on: September 12, 2006, 06:38:47 AM »
I have 2 related problems:

2, Sucrose haven't got any couple of OH groups which are cis, how could sucrose make deep blue solution with Cu(OH)2?
Did you inspected a spacial model of sucrose?
AWK

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