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But How do I find amps for part a? There seem to be two variables there.
The equation for electrochemical production of aluminum is2 Al2O3(aq) + 3 C(s) ⟶ 4 Al(l) + 3 CO2(g)
1kg of bauxite has .650 kg of Al2O3 and that has .344 kg of Al.Do I just set up a proportion of .344/1kg = 2 million tonnes/ x tonnes?So then the answer is 5.812 million metric tonnes?