June 07, 2020, 02:27:01 AM
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Topic: How much Na2EDTA.2H2O do i need to weigh to get a 0,01M solution in 250 ml water  (Read 155 times)

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Offline 1800chisaki

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i did the following;

n edta = c edta x V H2O
n edta = 0,01 x 250 ml = 2,5 mmol

do i need to multiply n by 2 since edta is a dihydrate? edta is in the H2Y2- form here

further: m edta = n edta x Mr edta
            m edta = 2,5 mmol x 372,24 mg/mmol = 930,6 g

Offline AWK

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Quote
2,5 mmol x 372,24 mg/mmol = 930,6 g
Wrong unit
AWK

Offline 1800chisaki

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2,5 mmol x 372,24 mg/mmol = 930,6 g
Wrong unit

typo, but is my calculation correct? edta being a dihydrate doesnt change anything?

Offline AWK

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After all, you took into account the molar mass of dihydrate.
AWK

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