For Claisen addition, the classic product is a 1,3 dicarbonyl. If I use ethyl chloroformate as the electrophile and the nucleophile is a symmetric ketone (meaning only a possible enolate), the product is a simply addition with ethyl chloroformate kicking off the -Cl group. When I google online or read the textbook, it seems people stops here.
But my question is: it appears to me that the ester part of the ethyl chloroformate is again a decent leaving group for Claisen reaction. Therefore, I would predict the final product should be a meso 1,3,5 tricarbonyl. (because of the plane of symmetry). Am I right? Or is it controlled by the concentration of both of the reactants?