April 24, 2024, 08:11:01 AM
Forum Rules: Read This Before Posting


Topic: Molarity  (Read 1144 times)

0 Members and 1 Guest are viewing this topic.

Offline Rexosaurus

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Molarity
« on: May 25, 2020, 02:43:08 PM »
I've tried this problem a couple times, but can't seem to come up with the proper answer.

Question:
Consumer products express concentrations in mg/volume or g/volume because the general public isn't familiar with molarity.
a) A medium-sized (296 mL) cup of coffee contains 0.10 g caffeine, C8H10N4O2. Express this concentration in molarity.


My work:
0.10 g C8H10N4O2/296 mL X 1mol/74g X 1 mL/10-3 L

I'm not sure where to go from here. I keep getting 4.56, which the textbook says is wrong. Is anyone able to point me in the right direction?

Offline chenbeier

  • Sr. Member
  • *****
  • Posts: 1348
  • Mole Snacks: +102/-22
  • Gender: Male
Re: Molarity
« Reply #1 on: May 25, 2020, 02:56:45 PM »
Check die molar mass of caffeine. 74 g/mol is to low.

Offline Rexosaurus

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Re: Molarity
« Reply #2 on: May 25, 2020, 03:03:43 PM »
Thank you!

Offline MNIO

  • Full Member
  • ****
  • Posts: 135
  • Mole Snacks: +12/-3
Re: Molarity
« Reply #3 on: May 26, 2020, 01:42:40 AM »
excellent setup... it's good to see you using factor label method.. also watch your sig figs

  0.10g caffeine       1 mol caffeine         1000mL
 ----------------- x --------------------- x ----------- = ___ M
     298mL              194.19g caffeine         1 L

this is all multiplication and division... the result is limited to what? 

Sponsored Links