Thank you for the comment.
Dissociation of the molecule is: R-NH2 + H2O --> R-NH3+ + OH-.
As pKa of 2-aminoacetophenone (subsequently called 2AAP) is said to be be 2,31 I think in plain water and with a low concentration of 2AAP (µm range) we will see roughly 1/200 part of the 2AAP to be dissociated.
Am I correct so far?
However, the problem (that is to say my problem) is what happens in a solution with an pH of 3,0? Where does the pH of the solvent come in in my dissociation formula above?
So, again, I am ashamed to admit that I am unable to do the calculation. Thats why I was asking for help, in the best case by providing the result.
Please excuse my being so hard of grasp...
With kind regards