August 12, 2020, 05:13:54 PM
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Offline tryteklitu

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Chemia
« on: July 12, 2020, 06:45:15 AM »
what reaction CuSO4 * 5H2O + 2NaNO2?

Offline chenbeier

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Re: Chemia
« Reply #1 on: July 12, 2020, 08:04:02 AM »
Probably nothing. What could react? What do you know of reduction power of nitrite and oxidation power of copper2+?

Offline tryteklitu

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Re: Chemia
« Reply #2 on: July 12, 2020, 08:54:37 AM »
copper will not change its valence. nitrogen will disproportionate with the release of nitric oxide

Offline tryteklitu

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Re: Chemia
« Reply #3 on: July 12, 2020, 09:05:33 AM »
there is no copper nitrite so I ask

Offline chenbeier

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Re: Chemia
« Reply #4 on: July 12, 2020, 09:11:52 AM »
If nitrite will disproportionate, which compounds would develop. Note oxidation number of nitrogen is + 3 in this case. Can that work?

Offline AWK

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Re: Chemia
« Reply #5 on: July 12, 2020, 09:33:41 AM »
When sodium nitrite is added to the copper salt solutions, the solution turns green. This indicates the formation of a complex compound. Copper(II) nitrite alone could not be isolated, because it will quickly oxidize with air oxygen to nitrate(V).
In more basic solutions, poorly soluble copper basic nitrite Cu(NO2)2·xCu(OH)2 (where x may be from 1 to 3) is formed.
With a large excess of KNO2, K3Cu(NO2)5 was obtained with a complex structure.
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Offline chenbeier

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Re: Chemia
« Reply #6 on: July 12, 2020, 09:55:28 AM »
But the question what asked was only to add coppersulfate and sodium nitrite. No alkaline envirement.

The only post I found the catalytical reaction of copper metal to nitrite in a german article from 1919. It describes the formimg of N2O , NO and nitrate.

https://onlinelibrary.wiley.com/doi/abs/10.1002/zaac.19191070108

Offline tryteklitu

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Re: Chemia
« Reply #7 on: July 12, 2020, 10:07:57 AM »
copper Has a coordination number of 4 instead of 5 or 6

 there are not so many free orbits

 since sodium nitrite can be crystallized by the presence of oxygen, I see no reason why this cannot be done with copper nitrate

 if it exists

 And you can always do that

 isolate the inert gas atmosphere

 or evaporate

 under reduced pressure

 the problem with copper nitrate is rather that copper has weak basic properties

 and nitrite

 would fall apart

 nitrous acid

 and copper hydroxide and next


9CuSO4*5H2O + 18NaNO2 = 4Cu2(OH)3NO3  + Cu(NO3)2 + 12NO + 9Na2SO4 + 39H2O

for now it is a theory but soon after I get the reagents They will react.  it may come down hot

Offline AWK

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Re: Chemia
« Reply #8 on: July 12, 2020, 10:28:22 AM »
Quote
copper Has a coordination number of 4 instead of 5 or 6

 there are not so many free orbits

 since sodium nitrite can be crystallized by the presence of oxygen, I see no reason why this cannot be done with copper nitrate

You forget about the catalytic properties of many metals.



It is very difficult to answer inaccurate questions or containing insufficient information (which is very common in this Forum). There is a lack of information on concentrations, proportions of reagents, or the order of adding reagents and the environment. Many reactions do not require such details, but in this case, it may be relevant.
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Offline chenbeier

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Re: Chemia
« Reply #9 on: July 12, 2020, 12:23:04 PM »
copper Has a coordination number of 4 instead of 5 or 6

 there are not so many free orbits

 since sodium nitrite can be crystallized by the presence of oxygen, I see no reason why this cannot be done with copper nitrate

 if it exists

 And you can always do that

 isolate the inert gas atmosphere

 or evaporate

 under reduced pressure

 the problem with copper nitrate is rather that copper has weak basic properties

 and nitrite

 would fall apart

 nitrous acid

 and copper hydroxide and next


9CuSO4*5H2O + 18NaNO2 = 4Cu2(OH)3NO3  + Cu(NO3)2 + 12NO + 9Na2SO4 + 39H2O

for now it is a theory but soon after I get the reagents They will react.  it may come down hot

Your equation make no sense .

CuSO4* 5 H2O is only existing as a solid.

In aquaeous solution you have [Cu(H2O)42+

Offline AWK

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Re: Chemia
« Reply #10 on: July 12, 2020, 12:37:07 PM »
Quote
Your equation make no sense .

CuSO4* 5 H2O is only existing as a solid.

In aquaeous solution you have [Cu(H2O)42+


Why?
The copper (II) nitrite that is being formed during solid reaction should be thermally decomposed starting from about 80°C.
AWK

Offline tryteklitu

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Re: Chemia
« Reply #11 on: July 12, 2020, 03:09:47 PM »
thanks for the attention and especially that copper can catalyze reductions to N2O. what to do I plan to pour concentrated substrate solutions in stoichiometric amounts. Then it may happen
2 [Cu (NO2) 2 (H2O) 2] <-> [Cu (NO2) 4] 2- + [Cu (H2O) 4] 2+
on one copper ion
[Cu (NO2) 4] 2- + H2O -> Cu (OH) 2 + 2NO3- + N2O

globally
2 [Cu (H2O) 4] 2+ 4NO2- -> Cu (OH) 2 + [Cu (H2O) 4] 2+ N2O + 2NO3- + 3H2O
or I wrote it earlier with NO

maybe, any suggestions on how to choose the parameters to create N2O and not NO?

Offline AWK

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Re: Chemia
« Reply #12 on: July 12, 2020, 03:35:29 PM »
This reaction can be very sensitive to temperature. You still haven't specified the conditions under which you want to react. Giving copper sulfate pentahydrate as a reagent suggests a reaction in the solid, and this involves heating. In this case, your overall reaction is false because an attempt to dehydrate copper(II) nitrate (which is a product of your reaction) by heating also leads to basic copper nitrate.
AWK

Offline chenbeier

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Re: Chemia
« Reply #13 on: July 13, 2020, 01:00:33 AM »
Quote
Your equation make no sense .

CuSO4* 5 H2O is only existing as a solid.

In aquaeous solution you have [Cu(H2O)42+


Why?
The copper (II) nitrite that is being formed during solid reaction should be thermally decomposed starting from about 80°C.

You didnt told in the beginning. I thought you dissolve both in water.

Offline tryteklitu

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Re: Chemia
« Reply #14 on: July 13, 2020, 06:15:13 AM »
Jak najbardziej będę rozpuszczał w wodzie najpierw  przygotuje stężone roztwory które następnie będę wlewał do wody.

Mod edit using google translate
Quote
As much as possible I will dissolve in water, first I will prepare concentrated solutions which I will then pour into water.
You should post in English
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