September 28, 2020, 06:38:38 PM
Forum Rules: Read This Before Posting


Topic: Industrial chemical problem  (Read 245 times)

0 Members and 1 Guest are viewing this topic.

Offline Alvaro

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Industrial chemical problem
« on: August 24, 2020, 06:16:27 AM »
Hello,

I want to react NO with UREA to reduce NO whose reaction is:
2NO + CO (NH2) 2 + ½ O2--------------------->2N2 + CO2 + 2H2O

The fact is that instead of UREA I have used NH3 to make it easier, then the reaction would be the following:
2NO + 2NH3 + ½ O2--------------------> 2N2 + 3H2O

I know the mole fraction of NO which is 0.0003 and also that of 02 which is 0.01848 (Both in the gas phase since it is the gas produced from combustion). The question is, how much liquid NH3 do I have to use to reduce the maximum amount of NO.

Thank you very much in advance.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 25981
  • Mole Snacks: +1698/-402
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Industrial chemical problem
« Reply #1 on: August 24, 2020, 01:07:44 PM »
What have you tried so far? Per forum rules you have to show your attempts at solving the problem to receive help.

Assuming they react quickly and completely this looks like a simple stoichiometry question. Assuming they don't and kinetics is involved, there is not enough data to give the answer.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info, pH-meter.info

Offline MNIO

  • Full Member
  • ****
  • Posts: 137
  • Mole Snacks: +12/-3
Re: Industrial chemical problem
« Reply #2 on: September 06, 2020, 10:09:01 PM »
why do you need to oxygen?
what catalyst are you using?
have you considered changing the residence time of your reactor?

Sponsored Links