January 22, 2021, 10:55:38 AM
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### Topic: Base Concentration calculation  (Read 858 times)

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#### Borek

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##### Re: Base Concentration calculation
« Reply #15 on: August 27, 2020, 05:14:42 PM »
0.112 mol / 3470 L = 3.17×10-5 M

Hydroxide concentration is twice that: 6.34×10-5 M

pOH = 4.2

Doesn't look right.

2 [OH-] = [Ca(OH)2]

Quite the opposite.
« Last Edit: August 27, 2020, 05:47:05 PM by Borek »
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#### Meter

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##### Re: Base Concentration calculation
« Reply #16 on: August 28, 2020, 05:42:35 AM »
0.112 mol / 3470 L = 3.17×10-5 M

Hydroxide concentration is twice that: 6.34×10-5 M

pOH = 4.2

Doesn't look right.

2 [OH-] = [Ca(OH)2]

Quite the opposite.
Christ I'm stupid. I had been up for ~24 hours when I tried to solve it.

Of course it is 2 [Ca(OH)2] = [OH-] and then I do get around twice what OP got using the same method otherwise. Thanks, Borek.

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