HX + H2O <-> H3O+ + X-
Ka = [ H3O+ ] [ X- ] / [ HA ]
The Ka term excludes the [H2O] in the denominator as [H2O] is fairly a constant in an aqueous system.
Just include [H2O] in the denominator to convert Ka to Keq
Keq = [ H3O+ ] [ X- ] / [ HA ] [H2O]
« Last Edit: September 13, 2004, 02:03:48 AM by geodome »
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