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Topic: Creating Basic Buffer  (Read 877 times)

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Offline fl0werb

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Creating Basic Buffer
« on: October 19, 2020, 06:30:44 PM »
I need to make a buffer solution with a PH of 10.10. I can use HCL, NaOH, C6H5ONa (PKb=4.00), CH3COONa (Pkb=9.25), and CH3COOH (PKa=4.75).

None of the acids have a PKa close to the PH, I know the pOH is roughly 4 so C6H5ONa is an ideal base. Not sure where to go from there.

Edit: I should have specified that I have to use two species to add to water to prepare the buffer. Then I have to find the ratio of moles of the two species.
« Last Edit: October 19, 2020, 07:46:18 PM by fl0werb »

Offline Babcock_Hall

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Re: Creating Basic Buffer
« Reply #1 on: October 19, 2020, 06:35:28 PM »
I think that you may be confusing pOH with something else.

Offline Borek

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Re: Creating Basic Buffer
« Reply #2 on: October 19, 2020, 06:48:51 PM »
How are pKa and pKb related?
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Offline fl0werb

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Re: Creating Basic Buffer
« Reply #3 on: October 19, 2020, 07:44:45 PM »
I'm not sure if I'm replying to the right reply, so I'll just reply to both.

My understanding of making a buffer is that it's ideal to use an acid that has a Pka close to the Ph, so I figured that it is also true that a base with a PKb close to the pOH is better.

Pka and Pkb sum to 14, so the Pka for the C6H5ONa is 10 (really close to PH so good!) but I don't know what other species to use with it.

Offline Babcock_Hall

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Re: Creating Basic Buffer
« Reply #4 on: October 19, 2020, 09:22:59 PM »
Are you familiar with the Henderson-Hasselbalch equation?

Offline fl0werb

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Re: Creating Basic Buffer
« Reply #5 on: October 19, 2020, 10:11:22 PM »
Yes.

So far what I've got to is

PH= Pka - log [acid/base]

Using the Pka from the conjugate acid of CH3COONa which would be 10, I then have .1= -log[acid/base]

I then found the ratio of acid to base to be .79

Now what I'm confused is to how much HCL I should add to the solution to produce that ratio of conjugate acid to base.

Offline Borek

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Re: Creating Basic Buffer
« Reply #6 on: October 20, 2020, 03:05:32 AM »
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