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Topic: Theoretical yield  (Read 774 times)

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Offline rkp

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Theoretical yield
« on: October 20, 2020, 02:07:13 PM »
The reaction used to create the product is:

x CoCl2·6H2O(aq) + y H2C2O4·2H2O(aq) → Cox(C2O4)y·(H2O)z(s)

Now that the formula for the product is known (previous section), you also know the values for the coefficients x and y. Based on the starting mass of CoCl2.6H2O and the fact that it is the limiting reagent, determine the mass of Cox(C2O4)y·(H2O)z product expected. This is the theoretical yield. In part 1, you found the actual yield of product. Calculate the percent yield.
CAN SOMEONE PLEASE HELP ME WITH THIS
THE ACTUAL YIELD IS 1.548
« Last Edit: October 20, 2020, 03:56:39 PM by Borek »

Offline chenbeier

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Re: Theoretical yield
« Reply #1 on: October 20, 2020, 02:21:05 PM »
What is the formula of the Product. First section is missing.
If you know the formula then you can calculate from the given mass of the educt via the mole the mass of the product. If you divide the given mass of the product through the calculated mass of theoretical product you get the yield.
« Last Edit: October 20, 2020, 03:56:49 PM by Borek »

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