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Only 75.23 moles are OK
I think I need to multiply 75.23 with 7.4/100. but I'm not sure.
Quote from: chimias223 on October 28, 2020, 04:58:44 PMI think I need to multiply 75.23 with 7.4/100. but I'm not sure.Idea is sound, but that's not what you did.
Have you ever heard of significant figures?
Question is poorly formulated in this aspect, it asks for using atomic masses to 3 decimal points, yet gives 6Li abundance to only two sigfigs.That being said, the number is OK, it is just a matter of a correct representation of its uncertainty.
The answer will be 5.567?
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