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Topic: A little help with gas laws homework please  (Read 1518 times)

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Offline lilmeer288

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A little help with gas laws homework please
« on: December 18, 2020, 02:14:07 PM »


I think I have question 2 answered aswell as the missing values, not sure if they are correct. If anyone can correct me and tell me why im wrong with my answers Id appreciated that. Im also currently stuck on question 3 and im not sure where to begin. Its telling me I have 6 mols of hydrochloric acid that reacted with magnesium. I want to say that I start off with a 1:6 ratio between HCl and Mg ? and multiply 0.0247 by 6 but im not sure if that is what im supposed to do

Offline AWK

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Re: A little help with gas laws homework please
« Reply #1 on: December 18, 2020, 03:03:06 PM »
For ratio HCl:Mg - read reaction and recall the definition of molar concentration.

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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #2 on: December 18, 2020, 03:09:06 PM »
The concentration formula is M=n/v. The volume of gas collected that im given is 51mL
so would that be. 1Mg : 2HCL = 0.0247 x 2 which equals 0.0494. So the moles for HCl is 0.494 and then I use the Molar concentration formula. M = n/v, M = 0.494/51  = 0.00096863 ? Idk If i did that right could you correct me if im wrong

Offline AWK

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Re: A little help with gas laws homework please
« Reply #3 on: December 18, 2020, 03:48:30 PM »
Quote
M = n/v
V is the volume of acid.

Volume of gas after temperature ans pressure correction is wrong (rather 58 cm3)
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #4 on: December 18, 2020, 04:05:05 PM »
I do not have the volume of hydrochloric acid. How can I figure that out ?

Offline AWK

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Re: A little help with gas laws homework please
« Reply #5 on: December 18, 2020, 04:07:50 PM »
You have to calculate them.
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #6 on: December 18, 2020, 04:14:08 PM »
If im correct I can rearrange the formula M=n/v to V = Mn to get V
Is 6 mol/L the Molar concentration ? which then I can do V = (6)(0.0494)
and then that means V is = 0.2964 L ?

Offline AWK

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Re: A little help with gas laws homework please
« Reply #7 on: December 18, 2020, 04:16:33 PM »
So simple rearragement of formula is wrong.
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #8 on: December 18, 2020, 04:26:37 PM »
Ah is it V = n/M which then it is V = 0.0494/6 which equals 0.00823333L ?

Offline AWK

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Re: A little help with gas laws homework please
« Reply #9 on: December 18, 2020, 04:30:33 PM »
Have you heard about significant figures?
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #10 on: December 18, 2020, 04:32:58 PM »
Yes, with sig figs it should be 0.0082 L, correct ?

Offline AWK

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Re: A little help with gas laws homework please
« Reply #11 on: December 18, 2020, 04:39:29 PM »
This is the volume that can be measured with a 10 ml graduated pipette (although the acid concentration is probably 6M, which is one significant figure) - I would use the value of 8.2 ml.
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #12 on: December 18, 2020, 04:40:40 PM »
Thank you so much, I appreciate the help. Is my answer for question 2 correct ? or did I do something wrong there aswell ?

Offline AWK

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Re: A little help with gas laws homework please
« Reply #13 on: December 18, 2020, 04:47:23 PM »
I commented on your value in my second post.
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Offline lilmeer288

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Re: A little help with gas laws homework please
« Reply #14 on: December 18, 2020, 04:51:18 PM »
Ah, how can I fix it. The pressure i determined for dry hydrogen is 103.28kPa and the moles for it is 0.0247 mol since it is a 1:1 ratio with Mg. I tried using PV= nRT to determine it and its wrong. I cant think of any other formula to use to determine the theoritcal volume of dry hydrogen

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