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Topic: AP chemistry  (Read 1729 times)

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Offline pt999

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AP chemistry
« on: December 28, 2020, 08:00:50 PM »
Hello! I have been assigned a review for topics 3.7 through 3.13. I am stuck on an FRQ, question 4c to be specific. The information I have been given is as follows

"After the experiment, the student learns that the precipitate,  AgCl(s) , is slightly soluble in water. To determine the solubility, the student mixes a sample of the precipitate with warm, distilled water to make a saturated solution. The student finds the following equation for the dissolution of  AgCl(s)  in water and a  Ksp  value at the temperature of the water.

AgCl(s)⇄Ag+(aq)+Cl−(aq)                    Ksp=4.0×10−10"

The information I have already is: 1.46 grams of AgCl, 0.0102 mols of AgCl, and 0.05 M Ag. The AP videos did not cover these kinds of equations yet, so I am very lost. Any help is appreciated!

Offline AWK

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Re: AP chemistry
« Reply #1 on: December 29, 2020, 02:35:15 AM »
AWK

Offline pt999

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Re: AP chemistry
« Reply #2 on: December 29, 2020, 11:17:15 AM »
I think im supposed to calculate molarity, at least thats what the people on reddit said… But Im given very little information to work with

Offline AWK

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Re: AP chemistry
« Reply #3 on: December 29, 2020, 11:35:16 AM »
For the solubility product, the concentration of ions or dissolved salt in a saturated solution is usually calculated (for AgCl these are the same numbers). You are given a specially crafted solubility product so that calculations can be done without a calculator. Please read the attached link.
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