Alright guys, it looks like I got what I was looking for.
From concentration of Calcium Hydroxide in the solution you antilog it.
pOH=-log0.0843 mol/L = 1.07417
pH = 14 - pOH - > 14 - 1.0742.
That was all. and to find the concentration I would use the negative of pH or pOH as a power of 10, so [OH^-]=10^-pOH or [H3O+]=10^-pH.
Thanks for the help though guys.