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Topic: URGENT HELP  (Read 179 times)

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Offline no-stretch8180

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URGENT HELP
« on: January 12, 2021, 09:30:33 AM »
2.13 g of a carbonate M2CO3 was dissolved in water and made up to 100 cm3
in
a volumetric flask. 10.0 cm3 of this solution required 18.50 cm3 of 0.100 mol dm−3
hydrochloric acid for neutralisation.
The equation below represents the reaction between the acid and the carbonate:
2HCl(aq)  M2CO3(aq) → 2MCl(aq)  H2O(l)  CO2(g)
a Calculate the amount in moles of HCl needed to neutralise 10.0 cm3 of the
carbonate solution.
b Using the equation above, write down the amount in moles of M2CO3 used
in the titration.
c Calculate the amount in moles of M2CO3 in 100 cm3 of the carbonate
solution.
d Calculate the molar mass of M2CO3
e Calculate the relative atomic mass of M. Give your answer to one decimal
place.
f Use the Periodic Table to identify M in the formula M2CO3

HOW DO I DO C?

Offline no-stretch8180

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Re: URGENT HELP
« Reply #1 on: January 12, 2021, 09:36:26 AM »
i dont know hwo to do c and onwards

Offline AWK

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Re: URGENT HELP
« Reply #2 on: January 12, 2021, 09:50:48 AM »
If you can calculate the moles in 10 cm3, why can't you calculate it in 100 cm3?
There is a simple mathematical relationship between the mass of a chemical compound and the number of moles in a sample.
AWK

Offline no-stretch8180

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Re: URGENT HELP
« Reply #3 on: January 12, 2021, 09:55:16 AM »
If you can calculate the moles in 10 cm3, why can't you calculate it in 100 cm3?
There is a simple mathematical relationship between the mass of a chemical compound and the number of moles in a sample.

so i did 0.1 x 0.1 = 0.01 is this right?

Offline AWK

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Re: URGENT HELP
« Reply #4 on: January 12, 2021, 10:11:35 AM »
If you can calculate the moles in 10 cm3, why can't you calculate it in 100 cm3?
There is a simple mathematical relationship between the mass of a chemical compound and the number of moles in a sample.

so i did 0.1 x 0.1 = 0.01 is this right?
And what do the reaction stoichiometry and titration say?

AWK

Offline no-stretch8180

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Re: URGENT HELP
« Reply #5 on: January 12, 2021, 10:13:14 AM »
If you can calculate the moles in 10 cm3, why can't you calculate it in 100 cm3?
There is a simple mathematical relationship between the mass of a chemical compound and the number of moles in a sample.

so i did 0.1 x 0.1 = 0.01 is this right?
And what do the reaction stoichiometry and titration say?

theres a 2:1 ratio for HCL:m2co3

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