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Topic: Hydroformylation of Olefins  (Read 1741 times)

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Offline Win,odd Dhamnekar

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Hydroformylation of Olefins
« on: February 03, 2021, 08:14:31 AM »
Hydroformylation of olefins yields aldehydes which further undergo reduction to give alcohols.

[tex] H_2 + CO +RCH = CH_2 \rightarrow RCH_2CH_2CHO \tag{1}[/tex]

[tex] H_2 + RCH_2CH_2CHO  \rightarrow RCH_2CH_2CH_2OH \tag{2}[/tex]

What is R in the reaction(1)?

The product doesn't seem to look alcoholCCOCin reaction (2). What is R in reaction (2)?
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Offline AWK

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Re: Hydroformylation of Olefins
« Reply #1 on: February 03, 2021, 08:59:47 AM »
The hydroformylation process is exceptionally well developed in technology textbooks, on the internet, and even on Wikipedia. You only need to read.
Depending on the reaction conditions, the product may be formate esters (not methyl ethers).
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Offline Orcio_87

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Re: Hydroformylation of Olefins
« Reply #2 on: March 06, 2021, 02:58:08 PM »
"R" in reaction 1 and 2 is simply the rest of molecule which is not important for reaction. It can be alkyl (-CH3, -CH2CH3) or aryl (-C6H5 - fenyl group) group or something else.
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