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Topic: Oxidation of 2-Butanol  (Read 664 times)

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Offline jackwhacky

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Oxidation of 2-Butanol
« on: February 27, 2021, 08:50:31 AM »
Hello. I saw my online teacher writing the equation for the oxidation of 2-butanol this way:

CH3CH(OH)CH2CH3+1/2 O2 ::equil:: CH3COCH2CH3 + H2O

My question is can I balance it this way correctly instead?

2CH3CH(OH)CH2CH3+O2 ::equil:: 2CH3COCH2CH3 + 2H2O

Thanks!

Offline Borek

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Re: Oxidation of 2-Butanol
« Reply #1 on: February 27, 2021, 09:43:18 AM »
In a way both are correct. Sometimes it is easier to make a point using coefficient of 1 for the most important reactant in the equation.

As far as I am aware IUPAC doesn't define whether the stoichiometric coefficients should be integer numbers, although in my experience the convention of using set of the smallest integers is the preferred one.
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Offline jackwhacky

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Re: Oxidation of 2-Butanol
« Reply #2 on: February 28, 2021, 02:01:09 PM »
I see! It makes much more sense now. Thank you  :)

Offline Vidya

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Re: Oxidation of 2-Butanol
« Reply #3 on: March 01, 2021, 11:46:04 PM »
In one case you are writing equation for one mole of butanol undergoing oxidation and in second case you are writing equation for two moles of butanol.

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