Topic: How many moles are in 326.19 g of FeBr? (Read 1182 times)

kk914 · « **on:** February 28, 2021, 08:59:00 PM »

Can someone explain how you got the solution and show all work.

billnotgatez · « **Reply #1 on:** February 28, 2021, 09:27:15 PM »

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billnotgatez · « **Reply #2 on:** February 28, 2021, 09:33:43 PM »

Quote from: kk914 on February 28, 2021, 08:59:00 PM

Can someone explain how you got the solution and show all work.

Which one
Iron(II) bromide, ferrous bromide FeBr₂
Iron(III) bromide, ferric bromide FeBr₃

Vidya · « **Reply #3 on:** March 01, 2021, 12:59:02 AM »

First check the correct formula --
Now convert grams to moles using molar mass.
1 moles of a compound mass equal to its molar mass.
Like H2O molecule
1 mole of H2O = 18.00 g

NotCitricAcid · « **Reply #4 on:** March 01, 2021, 08:56:18 PM »

moles = mass / molar mass

moles = 326.19 / 295.56

moles = 1.10363378..

AWK · « **Reply #5 on:** March 01, 2021, 11:23:51 PM »

This is the calculation for FeBr3. It still remains to determine the number of significant figures.

Topic: How many moles are in 326.19 g of FeBr? (Read 1182 times)

kk914

How many moles are in 326.19 g of FeBr?

billnotgatez

Re: How many moles are in 326.19 g of FeBr?

billnotgatez

Re: How many moles are in 326.19 g of FeBr?

Vidya

Re: How many moles are in 326.19 g of FeBr?

NotCitricAcid

Re: How many moles are in 326.19 g of FeBr?

AWK

Re: How many moles are in 326.19 g of FeBr?

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