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Topic: Why is the third compound the more acidic than the first?  (Read 629 times)

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Offline Roddy3

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Why is the third compound the more acidic than the first?
« on: March 04, 2021, 02:13:57 PM »
Picture of question: https://imgur.com/a/7gJfpil

Doesn't the additional nitrogen in compound III make it more basic than I since said nitrogen's lone pair cannot contribute to aromaticity and is free to function as a base?

Offline chenbeier

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Re: Why is the third compound the more acidic than the first?
« Reply #1 on: March 04, 2021, 02:21:00 PM »
Check mesomer structures, III can be stabilized over the second nitrogen if hydrogen is abstracted.

Offline spirochete

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Re: Why is the third compound the more acidic than the first?
« Reply #2 on: March 05, 2021, 03:15:27 PM »
Your reasoning contains an important and common misconception. The relative basicity of two compounds does not necessarily correlate with their relative acidity. For example, CH4 is both an extremely weak acid and an extremely weak base.

When they ask about relative acidity, you should consider the stability of the acid form compared to the conjugate base form. In other words, think about the ability of the molecules to lose a proton.

When they ask you about relative basicity, you should consider the stability of the base form compared to the conjugate acid form. In other words, think about the ability of the molecules to gain a proton.

In this question, molecule 3 (imidazole) happens to be both the most acidic AND the most basic. It has a relatively stable conjugate acid, and also a relatively stable conjugate base. These things happen sometimes.

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