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Topic: Understanding induction in acid-base reactions  (Read 622 times)

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Offline millefiori

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Understanding induction in acid-base reactions
« on: March 06, 2021, 04:56:08 PM »
ΘHello,
I am studying organic chemistry independently by working through David Klein's Organic Chemistry as a Second Language.

In this example (attached, 3.16 in the text), is the proton on the far left or the far right of the molecule more acidic?

O=C(O)C(F)(F)CCC(Cl)(Cl)C(=O)O


I would expect that because Cl is more electronegative than F, the C that the Cl atoms are bonded to would have a greater "partial positive" charge than the C which the F atoms are bonded to. If I'm correct, then this carbon would in turn induce a slightly partial negative charge on the C in the far-right carboxyl group, stabilizing its negative charge more than its counterpart on the left.

However the answer key tells me that I'm wrong. What am I misunderstanding?

Thank you for your suggestions!

Offline Orcio_87

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Re: Understanding induction in acid-base reactions
« Reply #1 on: March 06, 2021, 05:15:54 PM »
Quote
I would expect that because Cl is more electronegative than F

It's mistake. Fluorine is more electronegative than chlorine atom.

Hydrogen on left side of the molecule will be more acidic.

Offline millefiori

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Re: Understanding induction in acid-base reactions
« Reply #2 on: March 06, 2021, 06:45:45 PM »
Thanks Orcio. Guess I have to revisit the basics!

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