Hi again, I have trouble answering this question.
1) Calculate the reaction free energy of 2H2(g) + O2(g) <-----> 2H2O(g)
when the concentrations are 0.026 mol L-1 (H2), 0.33 mol L-1 (O2), and 1.84 mol L-1 (H2O), and the temperature is 700K. For this reaction Kc = 45 at 700 K.
A) 8.1kJ
B) 14.7 kJ
C) 34.3 kJ
D) 3.5 kJ
2) Which one of the following is a correct formation reaction?
A) C(diamond) ------> C(graphite)
B) H2(g) + O(g) --------> H2O(l)
C) C(graphite) + 4H(g) -------> CH4(g)
D) 6C(graphite) + 6H2O(s) --------> C6H12O6(s)
E) 2C(graphite) + 3H2(g) + ½O2(g) -------> C2H5OH(l)
I think the answer is A for question 2. I'm not sure :S
Many thanks