The problem is as follows:
Mg
2+ +CO
32- MgCO
3Using the K for the equilibrium, K
f=10
2.88 and the known concentration of MG species C
Mg=53.0 mM one should make an expression for [MG
2+]
[MgCO
3]/[Mg
2+][CO
32-]=K
ffrom this i get
[Mg
2+]=[MgCO
3]/[CO
32-]K
fI have tried to attack this problem from diffrent angles but still don't arrive at the book solution of:
C
Mg*1/(1+[CO
32-]K
f)
Help and ideas would be reatly appreciated