April 18, 2024, 07:57:27 PM
Forum Rules: Read This Before Posting


« previous next »
Pages: [1]   Go Down

Topic: Mole to mole stoichiometry problem  (Read 724 times)

0 Members and 1 Guest are viewing this topic.

Offline mg39

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Mole to mole stoichiometry problem
« on: April 10, 2021, 06:07:05 PM »
I'm having a really hard time understanding stoichiometry. The problem attached was answering "Calculate the number of moles of H2SO4 required to react with 18.79 moles of Al." and I got it wrong. Could somebody please point out what I'm doing wrong? Thanks for your time.
Logged

Offline Orcio_87

  • Full Member
  • ****
  • Posts: 440
  • Mole Snacks: +39/-3
Re: Mole to mole stoichiometry problem
« Reply #1 on: April 10, 2021, 06:50:57 PM »
You need 1,5 mole of H2SO4 for 1 mole of Al, not 3.
Logged

Offline Tamas

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Re: Mole to mole stoichiometry problem
« Reply #2 on: April 11, 2021, 06:53:35 AM »
Your equation is OK.

Just use your mind and think about what happens. You need 2 mol Al for the reaction with  3 mol H2SO4
If you have 18.79 moles of Al, in this case you need [18,79 * (3/2) ] mol H2SO4 
Logged
Pages: [1]   Go Up
« previous next »
Sponsored Links