December 02, 2021, 01:33:40 AM
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Topic: [itex]K_{sp} of PbCl_2[/itex]  (Read 531 times)

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Offline Win,odd Dhamnekar

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[itex]K_{sp} of PbCl_2[/itex]
« on: April 11, 2021, 01:11:28 PM »
Is author's answer correct ?

My answer:

 [itex]K_{sp}  of PbCl_2=1.7e-5[/itex], So the 13.0 M of NaCl is needed, which is impossible to obtain.

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Offline Orcio_Dojek

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Re: [itex]K_{sp} of PbCl_2[/itex]
« Reply #1 on: April 11, 2021, 02:44:03 PM »
Difference comes from given data - 1,7 x 10-5 and 1,0 x 10-4 for K = [Pb][Cl]2, and also that 20 ppb ≠ 1 x 10-7 M.

I get that concentration of Cl- should be bigger than 9,22  M for concentration of Pb+ lower than 2 x 10-8 M.

Offline Borek

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Re: [itex]K_{sp} of PbCl_2[/itex]
« Reply #2 on: April 11, 2021, 05:33:34 PM »
20 ppb ≠ 1 x 10-7 M.

Actually 1×10-7 M is 20 ppb (perhaps more like 21).
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Offline Orcio_Dojek

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Re: [itex]K_{sp} of PbCl_2[/itex]
« Reply #3 on: April 11, 2021, 05:53:27 PM »
@Borek Sorry, my error.

Now that I found that concentration of Cl- should be bigger than 13 M for Pb2+ smaller than 1 x 10-7 M (with K = [Pb][Cl]2 = 1,7 x 10-5).

Offline mjc123

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Re: [itex]K_{sp} of PbCl_2[/itex]
« Reply #4 on: April 12, 2021, 09:05:38 AM »
There seem to be different values out there in the literature. For example, on the wikipedia page for PbCl2, the quoted solubility and solubility product are inconsistent - 10.8 g/L implies Ksp = 2.85 x 10-4 M3.

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