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Topic: Balancing Chemical Equations  (Read 1184 times)

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Offline Sibbby2001

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Balancing Chemical Equations
« on: April 16, 2021, 12:54:42 PM »
FeCl3.6H2O + Ph2Hacac + NaOH = (FeIII(Ph2acac)3) + NaCl + H2O

Please can anyone help me balance this equation? Just note the 3 I's after Fe is the charge.

Offline Borek

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Re: Balancing Chemical Equations
« Reply #1 on: April 16, 2021, 01:05:24 PM »
What is Ph2Hacac intended to be? Is the disappearing H an acidic proton, or a typo?
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Offline Sibbby2001

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Re: Balancing Chemical Equations
« Reply #2 on: April 16, 2021, 01:12:22 PM »
The H in the (Ph2Hacac) is this 1,3-diphenyl-1,3-propanedione in its enol form.

Offline Sibbby2001

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Re: Balancing Chemical Equations
« Reply #3 on: April 16, 2021, 01:19:25 PM »
The ligand is abbreviated as Ph2Hacac with the deprotonated anionic form called Ph2acac

I've managed to get
FeCl3.6H2O + 3Ph2Hacac + 3NaOH = (FeIII(Ph2acac)3) + 3NaCl + 9H2O as my
answer. I don't think it's right though.
« Last Edit: April 16, 2021, 01:32:42 PM by Sibbby2001 »

Offline Borek

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Re: Balancing Chemical Equations
« Reply #4 on: April 16, 2021, 02:01:54 PM »
Looks OK to me.

FeCl3ยท6H2O + 3Ph2Hacac + 3NaOH :rarrow: Fe(Ph2acac)3 + 3NaCl + 9H2O
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Offline Sibbby2001

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Re: Balancing Chemical Equations
« Reply #5 on: April 16, 2021, 02:27:09 PM »
Thank you, Borek. I was told that it was incorrect. So I was looking over it to find an error that wasn't there.

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