June 14, 2021, 11:50:13 PM
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### Topic: Effective nuclear charge  (Read 217 times)

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#### j.s_g

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##### Effective nuclear charge
« on: May 03, 2021, 03:09:04 PM »
About the electron that is being analyzed for the effective nuclear charge equation: why is one electron always subtracted from the total numbers of electrons when you are calculating the shielding constant?
I've searched in many sites, but I couldn't understand this...
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#### Orcio_Dojek

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##### Re: Effective nuclear charge
« Reply #1 on: May 03, 2021, 04:27:25 PM »
Because shielding is a reduction in proton-electron attraction which a chosen electron receives because of the presence of electrons occupying inner shells.

#### j.s_g

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##### Re: Effective nuclear charge
« Reply #2 on: May 03, 2021, 04:39:49 PM »
@Orcio_Dojek Got it. Thank you very much!