March 28, 2024, 03:36:31 PM
Forum Rules: Read This Before Posting


Topic: Effective nuclear charge  (Read 846 times)

0 Members and 1 Guest are viewing this topic.

Offline j.s_g

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
  • Gender: Female
Effective nuclear charge
« on: May 03, 2021, 03:09:04 PM »
About the electron that is being analyzed for the effective nuclear charge equation: why is one electron always subtracted from the total numbers of electrons when you are calculating the shielding constant?
I've searched in many sites, but I couldn't understand this...
[

Offline Orcio_87

  • Full Member
  • ****
  • Posts: 440
  • Mole Snacks: +39/-3
Re: Effective nuclear charge
« Reply #1 on: May 03, 2021, 04:27:25 PM »
Because shielding is a reduction in proton-electron attraction which a chosen electron receives because of the presence of electrons occupying inner shells.

Offline j.s_g

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
  • Gender: Female
Re: Effective nuclear charge
« Reply #2 on: May 03, 2021, 04:39:49 PM »
@Orcio_Dojek Got it. Thank you very much!

Sponsored Links