Calculate ε at 25°C for the cell shown below, given the following data:

1.0 x 10^-3M Ni2+ 1.0M HCl

1.0M HCl AgCl(s)

Ksp for AgCl = 1.6 x 10^-10

A) 0.83V

B) 0.54V

C) 1.01V

D) 2.98V

E) cannot be determined from the data given

ANS: B

The answer I calculated is close to A, but the given answer is B.

Ni + 2Ag → Ni2+ + 2Ag

ε = 1.05 - 0.0596*0.5*log[10^-3/(√1.6x10^-10)^2]

= 0.85