Calculate ε at 25°C for the cell shown below, given the following data:
1.0 x 10^-3M Ni2+ 1.0M HCl
1.0M HCl AgCl(s)
Ksp for AgCl = 1.6 x 10^-10
A) 0.83V
B) 0.54V
C) 1.01V
D) 2.98V
E) cannot be determined from the data given
ANS: B
The answer I calculated is close to A, but the given answer is B.
Ni + 2Ag → Ni2+ + 2Ag
ε = 1.05 - 0.0596*0.5*log[10^-3/(√1.6x10^-10)^2]
= 0.85