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Topic: pH = -log[H+] for all acids, or only strong acids?  (Read 2294 times)

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Offline 3mpathogens

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pH = -log[H+] for all acids, or only strong acids?
« on: August 18, 2021, 11:29:15 PM »
My understanding:
pH = -log[H+] applies to all acids. For strong acids, the molar concentration of the acid itself can be used in place of [H+] given that strong acids dissociate completely (assuming we're using H2O. For weak acids, however, [H+] must be calculated.

Is this correct? Any nuances to add in? Thanks in advance.

Offline Borek

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Re: pH = -log[H+] for all acids, or only strong acids?
« Reply #1 on: August 19, 2021, 02:52:01 AM »
Is this correct?

As a first approximation - yes.

Quote
Any nuances to add in?

Plenty ;)

Even some strong acids are not as strong as it is commonly assumed (like nitric acid with pKa=-1), but there is another, much more important problem. Observed/measured pH is not just log of H+ concentration, it is log of H+ activity - for diluted solutions these are almost identical, the higher the concentration, the higher the ionic strength of the solution, the larger the difference. Google Debye-Huckel theory for a starting point.
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Offline 3mpathogens

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Re: pH = -log[H+] for all acids, or only strong acids?
« Reply #2 on: August 19, 2021, 07:42:12 AM »
Is this correct?

As a first approximation - yes.

Quote
Any nuances to add in?

Plenty ;)

Even some strong acids are not as strong as it is commonly assumed (like nitric acid with pKa=-1), but there is another, much more important problem. Observed/measured pH is not just log of H+ concentration, it is log of H+ activity - for diluted solutions these are almost identical, the higher the concentration, the higher the ionic strength of the solution, the larger the difference. Google Debye-Huckel theory for a starting point.

Thanks so much!

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